You are at a party with a friend. There are 20 people present including you and the friend. your friend makes you a wager that there are no two people at this party with the same birthday. Would you make the wager?
Note: Birthdays are identical if their month and date matches up. Year, hour, minute, seconds, are not part of the requirement.
The first person has 265/265 days do have birthday. The second only has 264/265. The third 263/265 and so on. When multiplying these numbers you'll get a chance of: ~48.49% So you would win with a chance of 51,5%!
if the party is clearly for a single man, why anyone would even come if they have birthday. they would probably make their own.
also, 20 people are mostly friends and family so you should know when is their bday
the chance that there are 2 people with the same birthday is relatively high, much higher than most people would expect. that's a classic example for probability theory or whatever you want to call it.
oh, well, I calculated with the right numbers, just wrote it down the wrong way...
In fact, it's even an unfair game. I calculated the chance, that no two people have the same birthday. So the chance, that two people have the same birthday is 100%- my calculated chance. Depends on which side you have to chose when your friend makes the wager!
the chance that there are 2 people with the same birthday is relatively high, much higher than most people would expect. that's a classic example for probability theory or whatever you want to call it.
ah crap, you are right
I guess that changes alot of things